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13055415613 is a prime number
BaseRepresentation
bin11000010100010100…
…11101010100111101
31020200212001211101121
430022022131110331
5203214141244423
65555250510541
7641345126122
oct141212352475
936625054347
1013055415613
11559a494a89
122644295451
131300a050c6
148bbc72749
1551624b45d
hex30a29d53d

13055415613 has 2 divisors, whose sum is σ = 13055415614. Its totient is φ = 13055415612.

The previous prime is 13055415587. The next prime is 13055415617. The reversal of 13055415613 is 31651455031.

13055415613 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12896327844 + 159087769 = 113562^2 + 12613^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13055415613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13055415617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527707806 + 6527707807.

It is an arithmetic number, because the mean of its divisors is an integer number (6527707807).

Almost surely, 213055415613 is an apocalyptic number.

It is an amenable number.

13055415613 is a deficient number, since it is larger than the sum of its proper divisors (1).

13055415613 is an equidigital number, since it uses as much as digits as its factorization.

13055415613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 13055415613 in words is "thirteen billion, fifty-five million, four hundred fifteen thousand, six hundred thirteen".