Base | Representation |
---|---|
bin | 111100110010110100… |
… | …0110111111011001011 |
3 | 110110222112211011201022 |
4 | 1321211220313323023 |
5 | 4114333340420043 |
6 | 135550434143055 |
7 | 12301153444421 |
oct | 1714550677313 |
9 | 413875734638 |
10 | 130554232523 |
11 | 50405508240 |
12 | 21376421a8b |
13 | c407967680 |
14 | 6466d3b111 |
15 | 35e1840868 |
hex | 1e65a37ecb |
130554232523 has 16 divisors (see below), whose sum is σ = 158667314400. Its totient is φ = 105778202880.
The previous prime is 130554232499. The next prime is 130554232553. The reversal of 130554232523 is 325232455031.
It is a cyclic number.
It is not a de Polignac number, because 130554232523 - 214 = 130554216139 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130554232553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15736658 + ... + 15744951.
It is an arithmetic number, because the mean of its divisors is an integer number (9916707150).
Almost surely, 2130554232523 is an apocalyptic number.
130554232523 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130554232523 is a deficient number, since it is larger than the sum of its proper divisors (28113081877).
130554232523 is a wasteful number, since it uses less digits than its factorization.
130554232523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31481662.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 130554232523 its reverse (325232455031), we get a palindrome (455786687554).
The spelling of 130554232523 in words is "one hundred thirty billion, five hundred fifty-four million, two hundred thirty-two thousand, five hundred twenty-three".
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