13055535320143 has 16 divisors (see below), whose sum is σ = 13870091171520. Its totient is φ = 12263050508544.

The previous prime is 13055535320101. The next prime is 13055535320173. The reversal of 13055535320143 is 34102353555031.

It is a cyclic number.

It is not a de Polignac number, because 13055535320143 - 2⁴¹ = 10856512064591 is a prime.

It is a super-3 number, since 3×13055535320143³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13055535320096 and 13055535320105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13055535320173) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16593196 + ... + 17362177.

It is an arithmetic number, because the mean of its divisors is an integer number (866880698220).

Almost surely, 2^{13055535320143} is an apocalyptic number.

13055535320143 is a deficient number, since it is larger than the sum of its proper divisors (814555851377).

13055535320143 is a wasteful number, since it uses less digits than its factorization.

13055535320143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33955698.

The product of its (nonzero) digits is 405000, while the sum is 40.

Adding to 13055535320143 its reverse (34102353555031), we get a palindrome (47157888875174).

The spelling of 13055535320143 in words is "thirteen trillion, fifty-five billion, five hundred thirty-five million, three hundred twenty thousand, one hundred forty-three".