Base | Representation |
---|---|
bin | 1011110111111011101010… |
… | …0010111000110001010000 |
3 | 1201020002121201000002122112 |
4 | 2331332322202320301100 |
5 | 3202400214020221034 |
6 | 43433344035124452 |
7 | 2515142223132632 |
oct | 275767242706120 |
9 | 51202551002575 |
10 | 13055535320144 |
11 | 4183904370799 |
12 | 156a300443728 |
13 | 7391934574b5 |
14 | 331c69964a52 |
15 | 17990ee767ce |
hex | bdfba8b8c50 |
13055535320144 has 40 divisors (see below), whose sum is σ = 25307255737920. Its totient is φ = 6524631360000.
The previous prime is 13055535320101. The next prime is 13055535320173. The reversal of 13055535320144 is 44102353555031.
It is a super-3 number, since 3×130555353201443 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 357383672 + ... + 357420200.
It is an arithmetic number, because the mean of its divisors is an integer number (632681393448).
Almost surely, 213055535320144 is an apocalyptic number.
It is an amenable number.
13055535320144 is a deficient number, since it is larger than the sum of its proper divisors (12251720417776).
13055535320144 is a wasteful number, since it uses less digits than its factorization.
13055535320144 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46659 (or 46653 counting only the distinct ones).
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 13055535320144 its reverse (44102353555031), we get a palindrome (57157888875175).
The spelling of 13055535320144 in words is "thirteen trillion, fifty-five billion, five hundred thirty-five million, three hundred twenty thousand, one hundred forty-four".
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