Base | Representation |
---|---|
bin | 11000010100011101… |
… | …10001110100101111 |
3 | 1020200221012100221011 |
4 | 30022032301310233 |
5 | 203214434020033 |
6 | 5555331050051 |
7 | 641360554012 |
oct | 141216616457 |
9 | 36627170834 |
10 | 13056548143 |
11 | 55a0098961 |
12 | 2644740927 |
13 | 1301010742 |
14 | 8bc089379 |
15 | 5163c1ccd |
hex | 30a3b1d2f |
13056548143 has 2 divisors, whose sum is σ = 13056548144. Its totient is φ = 13056548142.
The previous prime is 13056548137. The next prime is 13056548149. The reversal of 13056548143 is 34184565031.
It is a balanced prime because it is at equal distance from previous prime (13056548137) and next prime (13056548149).
It is a cyclic number.
It is not a de Polignac number, because 13056548143 - 25 = 13056548111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13056548096 and 13056548105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13056548149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6528274071 + 6528274072.
It is an arithmetic number, because the mean of its divisors is an integer number (6528274072).
Almost surely, 213056548143 is an apocalyptic number.
13056548143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13056548143 is an equidigital number, since it uses as much as digits as its factorization.
13056548143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 13056548143 in words is "thirteen billion, fifty-six million, five hundred forty-eight thousand, one hundred forty-three".
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