Base | Representation |
---|---|
bin | 11000010100100000… |
… | …11000101100111111 |
3 | 1020200221222202222021 |
4 | 30022100120230333 |
5 | 203220041011120 |
6 | 5555344101011 |
7 | 641364260401 |
oct | 141220305477 |
9 | 36627882867 |
10 | 13056969535 |
11 | 55a0356515 |
12 | 2644904767 |
13 | 130112a49c |
14 | 8bc158b71 |
15 | 516456aaa |
hex | 30a418b3f |
13056969535 has 4 divisors (see below), whose sum is σ = 15668363448. Its totient is φ = 10445575624.
The previous prime is 13056969533. The next prime is 13056969551. The reversal of 13056969535 is 53596965031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53596965031 = 61 ⋅878638771.
It is a cyclic number.
It is not a de Polignac number, because 13056969535 - 21 = 13056969533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13056969533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1305696949 + ... + 1305696958.
It is an arithmetic number, because the mean of its divisors is an integer number (3917090862).
Almost surely, 213056969535 is an apocalyptic number.
13056969535 is a deficient number, since it is larger than the sum of its proper divisors (2611393913).
13056969535 is an equidigital number, since it uses as much as digits as its factorization.
13056969535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2611393912.
The product of its (nonzero) digits is 3280500, while the sum is 52.
The spelling of 13056969535 in words is "thirteen billion, fifty-six million, nine hundred sixty-nine thousand, five hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •