Base | Representation |
---|---|
bin | 1011111000010111101011… |
… | …0000101000100000110100 |
3 | 1201020211000202211022202202 |
4 | 2332011322300220200310 |
5 | 3203011114102210330 |
6 | 43441030142324032 |
7 | 2515526453265665 |
oct | 276057260504064 |
9 | 51224022738682 |
10 | 13063055116340 |
11 | 4187013072999 |
12 | 156b85a889618 |
13 | 739ac1356c48 |
14 | 33238054b36c |
15 | 179c00219445 |
hex | be17ac28834 |
13063055116340 has 24 divisors (see below), whose sum is σ = 27460494000072. Its totient is φ = 5219873807360.
The previous prime is 13063055116337. The next prime is 13063055116357. The reversal of 13063055116340 is 4361155036031.
It can be written as a sum of positive squares in 4 ways, for example, as 7199712499984 + 5863342616356 = 2683228^2 + 2421434^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13063055116294 and 13063055116303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 334244921 + ... + 334284000.
It is an arithmetic number, because the mean of its divisors is an integer number (1144187250003).
Almost surely, 213063055116340 is an apocalyptic number.
13063055116340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13063055116340 is an abundant number, since it is smaller than the sum of its proper divisors (14397438883732).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13063055116340 is a wasteful number, since it uses less digits than its factorization.
13063055116340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 668529907 (or 668529905 counting only the distinct ones).
The product of its (nonzero) digits is 97200, while the sum is 38.
The spelling of 13063055116340 in words is "thirteen trillion, sixty-three billion, fifty-five million, one hundred sixteen thousand, three hundred forty".
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