Base | Representation |
---|---|
bin | 1011111000100000001100… |
… | …0100111101100001100111 |
3 | 1201021000221011021111120112 |
4 | 2332020003010331201213 |
5 | 3203030310042143123 |
6 | 43442045121323235 |
7 | 2515640233601612 |
oct | 276100304754147 |
9 | 51230834244515 |
10 | 13065342146663 |
11 | 4187a870356a4 |
12 | 157019879651b |
13 | 73a09710a921 |
14 | 33251a1a1179 |
15 | 179cd5dc7d78 |
hex | be20313d867 |
13065342146663 has 4 divisors (see below), whose sum is σ = 13833891684720. Its totient is φ = 12296792608608.
The previous prime is 13065342146653. The next prime is 13065342146671. The reversal of 13065342146663 is 36664124356031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13065342146663 - 218 = 13065341884519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13065342146603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 384274769003 + ... + 384274769036.
It is an arithmetic number, because the mean of its divisors is an integer number (3458472921180).
Almost surely, 213065342146663 is an apocalyptic number.
13065342146663 is a deficient number, since it is larger than the sum of its proper divisors (768549538057).
13065342146663 is an equidigital number, since it uses as much as digits as its factorization.
13065342146663 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 768549538056.
The product of its (nonzero) digits is 5598720, while the sum is 50.
The spelling of 13065342146663 in words is "thirteen trillion, sixty-five billion, three hundred forty-two million, one hundred forty-six thousand, six hundred sixty-three".
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