Base | Representation |
---|---|
bin | 111100110110010110… |
… | …0000101001001000111 |
3 | 110111021210101110212012 |
4 | 1321230230011021013 |
5 | 4120104130413412 |
6 | 140010301244435 |
7 | 12304121016266 |
oct | 1715454051107 |
9 | 414253343765 |
10 | 130672513607 |
11 | 504662555a9 |
12 | 213a9b6371b |
13 | c42630c08c |
14 | 647892a5dd |
15 | 35ebe06c22 |
hex | 1e6cb05247 |
130672513607 has 2 divisors, whose sum is σ = 130672513608. Its totient is φ = 130672513606.
The previous prime is 130672513589. The next prime is 130672513679. The reversal of 130672513607 is 706315276031.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (706315276031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130672513607 - 210 = 130672512583 is a prime.
It is a super-3 number, since 3×1306725136073 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130672513507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65336256803 + 65336256804.
It is an arithmetic number, because the mean of its divisors is an integer number (65336256804).
Almost surely, 2130672513607 is an apocalyptic number.
130672513607 is a deficient number, since it is larger than the sum of its proper divisors (1).
130672513607 is an equidigital number, since it uses as much as digits as its factorization.
130672513607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 158760, while the sum is 41.
Adding to 130672513607 its reverse (706315276031), we get a palindrome (836987789638).
The spelling of 130672513607 in words is "one hundred thirty billion, six hundred seventy-two million, five hundred thirteen thousand, six hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •