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130681132613 is a prime number
BaseRepresentation
bin111100110110100110…
…0111101011001000101
3110111022101121100220122
41321231030331121011
54120113332220423
6140011210111325
712304254204503
oct1715514753105
9414271540818
10130681132613
1150470102149
12213b0a1b545
13c428039195
146479b31673
1535eca5a8c8
hex1e6d33d645

130681132613 has 2 divisors, whose sum is σ = 130681132614. Its totient is φ = 130681132612.

The previous prime is 130681132607. The next prime is 130681132619. The reversal of 130681132613 is 316231186031.

It is a balanced prime because it is at equal distance from previous prime (130681132607) and next prime (130681132619).

It can be written as a sum of positive squares in only one way, i.e., 103456792609 + 27224340004 = 321647^2 + 164998^2 .

It is a cyclic number.

It is not a de Polignac number, because 130681132613 - 214 = 130681116229 is a prime.

It is a super-3 number, since 3×1306811326133 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130681132619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65340566306 + 65340566307.

It is an arithmetic number, because the mean of its divisors is an integer number (65340566307).

Almost surely, 2130681132613 is an apocalyptic number.

It is an amenable number.

130681132613 is a deficient number, since it is larger than the sum of its proper divisors (1).

130681132613 is an equidigital number, since it uses as much as digits as its factorization.

130681132613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 130681132613 in words is "one hundred thirty billion, six hundred eighty-one million, one hundred thirty-two thousand, six hundred thirteen".