13074142541 has 4 divisors (see below), whose sum is σ = 13074436032. Its totient is φ = 13073849052.

The previous prime is 13074142537. The next prime is 13074142547. The reversal of 13074142541 is 14524147031.

13074142541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14524147031 = 61 ⋅238100771.

It is a cyclic number.

It is not a de Polignac number, because 13074142541 - 2² = 13074142537 is a prime.

It is a super-3 number, since 3×13074142541³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13074142498 and 13074142507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13074142547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64595 + ... + 174128.

It is an arithmetic number, because the mean of its divisors is an integer number (3268609008).

Almost surely, 2^13074142541 is an apocalyptic number.

It is an amenable number.

13074142541 is a deficient number, since it is larger than the sum of its proper divisors (293491).

13074142541 is an equidigital number, since it uses as much as digits as its factorization.

13074142541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 293490.

The product of its (nonzero) digits is 13440, while the sum is 32.

Adding to 13074142541 its reverse (14524147031), we get a palindrome (27598289572).

The spelling of 13074142541 in words is "thirteen billion, seventy-four million, one hundred forty-two thousand, five hundred forty-one".