Base | Representation |
---|---|
bin | 111101000000000110… |
… | …1011000110011110111 |
3 | 110112010121122010020011 |
4 | 1322000031120303313 |
5 | 4121242000341043 |
6 | 140103000521051 |
7 | 12315205505206 |
oct | 1720015306367 |
9 | 415117563204 |
10 | 131000012023 |
11 | 50614100a51 |
12 | 2147b780187 |
13 | c47911731a |
14 | 64aa21b23d |
15 | 361aa4859d |
hex | 1e80358cf7 |
131000012023 has 2 divisors, whose sum is σ = 131000012024. Its totient is φ = 131000012022.
The previous prime is 131000011973. The next prime is 131000012029. The reversal of 131000012023 is 320210000131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131000012023 - 233 = 122410077431 is a prime.
It is a super-2 number, since 2×1310000120232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131000011994 and 131000012012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131000012029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500006011 + 65500006012.
It is an arithmetic number, because the mean of its divisors is an integer number (65500006012).
Almost surely, 2131000012023 is an apocalyptic number.
131000012023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000012023 is an equidigital number, since it uses as much as digits as its factorization.
131000012023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 131000012023 its reverse (320210000131), we get a palindrome (451210012154).
The spelling of 131000012023 in words is "one hundred thirty-one billion, twelve thousand, twenty-three".
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