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131000012023 is a prime number
BaseRepresentation
bin111101000000000110…
…1011000110011110111
3110112010121122010020011
41322000031120303313
54121242000341043
6140103000521051
712315205505206
oct1720015306367
9415117563204
10131000012023
1150614100a51
122147b780187
13c47911731a
1464aa21b23d
15361aa4859d
hex1e80358cf7

131000012023 has 2 divisors, whose sum is σ = 131000012024. Its totient is φ = 131000012022.

The previous prime is 131000011973. The next prime is 131000012029. The reversal of 131000012023 is 320210000131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131000012023 - 233 = 122410077431 is a prime.

It is a super-2 number, since 2×1310000120232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000011994 and 131000012012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000012029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500006011 + 65500006012.

It is an arithmetic number, because the mean of its divisors is an integer number (65500006012).

Almost surely, 2131000012023 is an apocalyptic number.

131000012023 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000012023 is an equidigital number, since it uses as much as digits as its factorization.

131000012023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 131000012023 its reverse (320210000131), we get a palindrome (451210012154).

The spelling of 131000012023 in words is "one hundred thirty-one billion, twelve thousand, twenty-three".