131000024417 has 2 divisors, whose sum is σ = 131000024418. Its totient is φ = 131000024416.

The previous prime is 131000024383. The next prime is 131000024429. The reversal of 131000024417 is 714420000131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128852999521 + 2147024896 = 358961^2 + 46336^2 .

It is an emirp because it is prime and its reverse (714420000131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131000024417 is a prime.

It is a super-2 number, since 2×131000024417² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000024392 and 131000024401.

It is not a weakly prime, because it can be changed into another prime (131000024117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500012208 + 65500012209.

It is an arithmetic number, because the mean of its divisors is an integer number (65500012209).

Almost surely, 2^131000024417 is an apocalyptic number.

It is an amenable number.

131000024417 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000024417 is an equidigital number, since it uses as much as digits as its factorization.

131000024417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 23.

Adding to 131000024417 its reverse (714420000131), we get a palindrome (845420024548).

The spelling of 131000024417 in words is "one hundred thirty-one billion, twenty-four thousand, four hundred seventeen".