Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …010001011001100010011101 |
3 | 122011211110222100110100002112 |
4 | 131302103102101121202131 |
5 | 114132301030224220123 |
6 | 1142340325542003405 |
7 | 36410303605064534 |
oct | 3562232221314235 |
9 | 564743870410075 |
10 | 131000030304413 |
11 | 38816889a41296 |
12 | 12838825116565 |
13 | 5813332c0141a |
14 | 244c61465331b |
15 | 10229287e8d78 |
hex | 7724d245989d |
131000030304413 has 4 divisors (see below), whose sum is σ = 131004737991360. Its totient is φ = 130995322617468.
The previous prime is 131000030304389. The next prime is 131000030304433. The reversal of 131000030304413 is 314403030000131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131000030304413 - 218 = 131000030042269 is a prime.
It is a super-2 number, since 2×1310000303044132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000030304433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2353801733 + ... + 2353857386.
It is an arithmetic number, because the mean of its divisors is an integer number (32751184497840).
Almost surely, 2131000030304413 is an apocalyptic number.
It is an amenable number.
131000030304413 is a deficient number, since it is larger than the sum of its proper divisors (4707686947).
131000030304413 is an equidigital number, since it uses as much as digits as its factorization.
131000030304413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4707686946.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131000030304413 its reverse (314403030000131), we get a palindrome (445403060304544).
The spelling of 131000030304413 in words is "one hundred thirty-one trillion, thirty million, three hundred four thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •