Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …010001011010111111011111 |
3 | 122011211110222100110122021001 |
4 | 131302103102101122333133 |
5 | 114132301030224412432 |
6 | 1142340325542051131 |
7 | 36410303605121101 |
oct | 3562232221327737 |
9 | 564743870418231 |
10 | 131000030310367 |
11 | 38816889a45809 |
12 | 12838825119aa7 |
13 | 5813332c0404a |
14 | 244c614655571 |
15 | 10229287ea9e7 |
hex | 7724d245afdf |
131000030310367 has 2 divisors, whose sum is σ = 131000030310368. Its totient is φ = 131000030310366.
The previous prime is 131000030310323. The next prime is 131000030310407. The reversal of 131000030310367 is 763013030000131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131000030310367 is a prime.
It is a super-2 number, since 2×1310000303103672 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131000030310167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500015155183 + 65500015155184.
It is an arithmetic number, because the mean of its divisors is an integer number (65500015155184).
Almost surely, 2131000030310367 is an apocalyptic number.
131000030310367 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000030310367 is an equidigital number, since it uses as much as digits as its factorization.
131000030310367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 28.
Adding to 131000030310367 its reverse (763013030000131), we get a palindrome (894013060310498).
The spelling of 131000030310367 in words is "one hundred thirty-one trillion, thirty million, three hundred ten thousand, three hundred sixty-seven".
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