Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …010001011011000000000111 |
3 | 122011211110222100110122022112 |
4 | 131302103102101123000013 |
5 | 114132301030224413112 |
6 | 1142340325542051235 |
7 | 36410303605121156 |
oct | 3562232221330007 |
9 | 564743870418275 |
10 | 131000030310407 |
11 | 38816889a45845 |
12 | 12838825119b1b |
13 | 5813332c0407b |
14 | 244c61465559d |
15 | 10229287eaa22 |
hex | 7724d245b007 |
131000030310407 has 2 divisors, whose sum is σ = 131000030310408. Its totient is φ = 131000030310406.
The previous prime is 131000030310367. The next prime is 131000030310473. The reversal of 131000030310407 is 704013030000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131000030310407 - 226 = 130999963201543 is a prime.
It is a super-2 number, since 2×1310000303104072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131000030310497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500015155203 + 65500015155204.
It is an arithmetic number, because the mean of its divisors is an integer number (65500015155204).
Almost surely, 2131000030310407 is an apocalyptic number.
131000030310407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000030310407 is an equidigital number, since it uses as much as digits as its factorization.
131000030310407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 23.
Adding to 131000030310407 its reverse (704013030000131), we get a palindrome (835013060310538).
The spelling of 131000030310407 in words is "one hundred thirty-one trillion, thirty million, three hundred ten thousand, four hundred seven".
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