13100003233001 has 2 divisors, whose sum is σ = 13100003233002. Its totient is φ = 13100003233000.

The previous prime is 13100003232997. The next prime is 13100003233003. The reversal of 13100003233001 is 10033230000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9493331265625 + 3606671967376 = 3081125^2 + 1899124^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100003233001 - 2² = 13100003232997 is a prime.

It is a super-3 number, since 3×13100003233001³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13100003233003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13100003233003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550001616500 + 6550001616501.

It is an arithmetic number, because the mean of its divisors is an integer number (6550001616501).

Almost surely, 2^{13100003233001} is an apocalyptic number.

It is an amenable number.

13100003233001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100003233001 is an equidigital number, since it uses as much as digits as its factorization.

13100003233001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13100003233001 its reverse (10033230000131), we get a palindrome (23133233233132).

The spelling of 13100003233001 in words is "thirteen trillion, one hundred billion, three million, two hundred thirty-three thousand, one".