13100003324341 has 4 divisors (see below), whose sum is σ = 13100049031552. Its totient is φ = 13099957617132.

The previous prime is 13100003324329. The next prime is 13100003324453. The reversal of 13100003324341 is 14342330000131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100003324341 - 2³³ = 13091413389749 is a prime.

It is a super-2 number, since 2×13100003324341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100003624341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22420965 + ... + 22997818.

It is an arithmetic number, because the mean of its divisors is an integer number (3275012257888).

Almost surely, 2^{13100003324341} is an apocalyptic number.

It is an amenable number.

13100003324341 is a deficient number, since it is larger than the sum of its proper divisors (45707211).

13100003324341 is an equidigital number, since it uses as much as digits as its factorization.

13100003324341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45707210.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13100003324341 its reverse (14342330000131), we get a palindrome (27442333324472).

The spelling of 13100003324341 in words is "thirteen trillion, one hundred billion, three million, three hundred twenty-four thousand, three hundred forty-one".