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1310001020003 = 13100769309231
BaseRepresentation
bin10011000100000010001…
…001010011110001100011
311122020100020000220112102
4103010002021103301203
5132430340230120003
62441450044121015
7163434021642164
oct23040211236143
94566306026472
101310001020003
11465628473585
12191a7883616b
13966c0080c60
14475938d576b
1524121e35588
hex13102253c63

1310001020003 has 4 divisors (see below), whose sum is σ = 1410770329248. Its totient is φ = 1209231710760.

The previous prime is 1310001019997. The next prime is 1310001020117. The reversal of 1310001020003 is 3000201000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310001020003 - 216 = 1310000954467 is a prime.

It is a super-2 number, since 2×13100010200032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310001320003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50384654603 + ... + 50384654628.

It is an arithmetic number, because the mean of its divisors is an integer number (352692582312).

Almost surely, 21310001020003 is an apocalyptic number.

1310001020003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1310001020003 is a deficient number, since it is larger than the sum of its proper divisors (100769309245).

1310001020003 is a wasteful number, since it uses less digits than its factorization.

1310001020003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100769309244.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 1310001020003 its reverse (3000201000131), we get a palindrome (4310202020134).

The spelling of 1310001020003 in words is "one trillion, three hundred ten billion, one million, twenty thousand, three".

Divisors: 1 13 100769309231 1310001020003