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131000102400413 is a prime number
BaseRepresentation
bin11101110010010011010110…
…100100011011000110011101
3122011211111011101010012012202
4131302103112210123012131
5114132301202203303123
61142340341035141245
736410305441641131
oct3562232644330635
9564744141105182
10131000102400413
1138816916704064
12128388452a4825
135813344b24c8c
14244c62005d3c1
15102292ecdaa28
hex7724d691b19d

131000102400413 has 2 divisors, whose sum is σ = 131000102400414. Its totient is φ = 131000102400412.

The previous prime is 131000102400371. The next prime is 131000102400437. The reversal of 131000102400413 is 314004201000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72948305196484 + 58051797203929 = 8540978^2 + 7619173^2 .

It is a cyclic number.

It is not a de Polignac number, because 131000102400413 - 28 = 131000102400157 is a prime.

It is a super-2 number, since 2×1310001024004132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000102400463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500051200206 + 65500051200207.

It is an arithmetic number, because the mean of its divisors is an integer number (65500051200207).

Almost surely, 2131000102400413 is an apocalyptic number.

It is an amenable number.

131000102400413 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000102400413 is an equidigital number, since it uses as much as digits as its factorization.

131000102400413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 131000102400413 its reverse (314004201000131), we get a palindrome (445004303400544).

The spelling of 131000102400413 in words is "one hundred thirty-one trillion, one hundred two million, four hundred thousand, four hundred thirteen".