131000112 has 80 divisors (see below), whose sum is σ = 381404160. Its totient is φ = 43041600.

The previous prime is 131000087. The next prime is 131000161. The reversal of 131000112 is 211000131.

It is a super-2 number, since 2×131000112² = 34322058688025088, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 131000094 and 131000103.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28537 + ... + 32807.

It is an arithmetic number, because the mean of its divisors is an integer number (4767552).

Almost surely, 2^131000112 is an apocalyptic number.

131000112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (190702080).

131000112 is an abundant number, since it is smaller than the sum of its proper divisors (250404048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000112 is a wasteful number, since it uses less digits than its factorization.

131000112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4359 (or 4347 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

The square root of 131000112 is about 11445.5280350013. The cubic root of 131000112 is about 507.8754525512.

Adding to 131000112 its reverse (211000131), we get a palindrome (342000243).

The spelling of 131000112 in words is "one hundred thirty-one million, one hundred twelve", and thus it is an aban number.