13100011320 has 384 divisors, whose sum is σ = 46533450240. Its totient is φ = 2923361280.

The previous prime is 13100011313. The next prime is 13100011321. The reversal of 13100011320 is 2311000131.

It is a super-2 number, since 2×13100011320² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 13100011296 and 13100011305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100011321) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 17630869 + ... + 17631611.

It is an arithmetic number, because the mean of its divisors is an integer number (121180860).

Almost surely, 2^13100011320 is an apocalyptic number.

13100011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100011320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23266725120).

13100011320 is an abundant number, since it is smaller than the sum of its proper divisors (33433438920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100011320 is a wasteful number, since it uses less digits than its factorization.

13100011320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 843 (or 820 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 13100011320 its reverse (2311000131), we get a palindrome (15411011451).

The spelling of 13100011320 in words is "thirteen billion, one hundred million, eleven thousand, three hundred twenty".