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13100020023304 = 231637502502913
BaseRepresentation
bin1011111010100001011000…
…0010100100000000001000
31201101100102220211011100001
42332220112002210000020
53204112320111221204
643510022140452344
72521305464644024
oct276502602440010
951340386734301
1013100020023304
1141a0761871685
121576a5624a0b4
13740432688a66
143340899b9384
1517ab655294a4
hexbea160a4008

13100020023304 has 8 divisors (see below), whose sum is σ = 24562537543710. Its totient is φ = 6550010011648.

The previous prime is 13100020023283. The next prime is 13100020023319. The reversal of 13100020023304 is 40332002000131.

It can be written as a sum of positive squares in only one way, i.e., 13093180402500 + 6839620804 = 3618450^2 + 82702^2 .

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-2 number, since 2×131000200233042 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 818751251449 + ... + 818751251464.

Almost surely, 213100020023304 is an apocalyptic number.

It is an amenable number.

13100020023304 is a deficient number, since it is larger than the sum of its proper divisors (11462517520406).

13100020023304 is a wasteful number, since it uses less digits than its factorization.

13100020023304 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1637502502919 (or 1637502502915 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13100020023304 its reverse (40332002000131), we get a palindrome (53432022023435).

The spelling of 13100020023304 in words is "thirteen trillion, one hundred billion, twenty million, twenty-three thousand, three hundred four".

Divisors: 1 2 4 8 1637502502913 3275005005826 6550010011652 13100020023304