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131000204403 = 3223632851229
BaseRepresentation
bin111101000000000111…
…0000111110001110011
3110112010121222220010100
41322000032013301303
54121242023020103
6140103005003443
712315210236115
oct1720016076163
9415117886110
10131000204403
1150614222542
122147b853583
13c479183a63
1464aa26b3b5
15361aa855a3
hex1e80387c73

131000204403 has 12 divisors (see below), whose sum is σ = 197449583760. Its totient is φ = 83536362096.

The previous prime is 131000204399. The next prime is 131000204453. The reversal of 131000204403 is 304402000131.

It is not a de Polignac number, because 131000204403 - 22 = 131000204399 is a prime.

It is a super-2 number, since 2×1310002044032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131000204453) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 316425408 + ... + 316425821.

It is an arithmetic number, because the mean of its divisors is an integer number (16454131980).

Almost surely, 2131000204403 is an apocalyptic number.

131000204403 is a deficient number, since it is larger than the sum of its proper divisors (66449379357).

131000204403 is a wasteful number, since it uses less digits than its factorization.

131000204403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 632851258 (or 632851255 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 131000204403 its reverse (304402000131), we get a palindrome (435402204534).

The spelling of 131000204403 in words is "one hundred thirty-one billion, two hundred four thousand, four hundred three".

Divisors: 1 3 9 23 69 207 632851229 1898553687 5695661061 14555578267 43666734801 131000204403