Base | Representation |
---|---|
bin | 11000011001101001… |
… | …00111010111000111 |
3 | 1020210222000000202001 |
4 | 30030310213113013 |
5 | 203312101134231 |
6 | 10003522530131 |
7 | 642426225415 |
oct | 141464472707 |
9 | 36728000661 |
10 | 13100021191 |
11 | 56126908a4 |
12 | 2657206947 |
13 | 130a02203a |
14 | 8c3b642b5 |
15 | 51a10cb61 |
hex | 30cd275c7 |
13100021191 has 2 divisors, whose sum is σ = 13100021192. Its totient is φ = 13100021190.
The previous prime is 13100021189. The next prime is 13100021203. The reversal of 13100021191 is 19112000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100021191 - 21 = 13100021189 is a prime.
It is a super-2 number, since 2×131000211912 (a number of 21 digits) contains 22 as substring.
Together with 13100021189, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100021111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550010595 + 6550010596.
It is an arithmetic number, because the mean of its divisors is an integer number (6550010596).
Almost surely, 213100021191 is an apocalyptic number.
13100021191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100021191 is an equidigital number, since it uses as much as digits as its factorization.
13100021191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
The spelling of 13100021191 in words is "thirteen billion, one hundred million, twenty-one thousand, one hundred ninety-one".
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