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13100022022 = 26550011011
BaseRepresentation
bin11000011001101001…
…00111100100000110
31020210222000001212211
430030310213210012
5203312101201042
610003522534034
7642426231013
oct141464474406
936728001784
1013100022022
11561269148a
12265720731a
13130a022529
148c3b6470a
1551a10d017
hex30cd27906

13100022022 has 4 divisors (see below), whose sum is σ = 19650033036. Its totient is φ = 6550011010.

The previous prime is 13100021969. The next prime is 13100022043. The reversal of 13100022022 is 22022000131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131000220222 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100021993 and 13100022011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275005504 + ... + 3275005507.

It is an arithmetic number, because the mean of its divisors is an integer number (4912508259).

Almost surely, 213100022022 is an apocalyptic number.

13100022022 is a deficient number, since it is larger than the sum of its proper divisors (6550011014).

13100022022 is an equidigital number, since it uses as much as digits as its factorization.

13100022022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6550011013.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 13100022022 its reverse (22022000131), we get a palindrome (35122022153).

The spelling of 13100022022 in words is "thirteen billion, one hundred million, twenty-two thousand, twenty-two".

Divisors: 1 2 6550011011 13100022022