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13100023 is a prime number
BaseRepresentation
bin110001111110…
…001111110111
3220122112212001
4301332033313
511323200043
61144440131
7216230326
oct61761767
926575761
1013100023
117438272
124479047
1329388c1
141a500bd
15123b74d
hexc7e3f7

13100023 has 2 divisors, whose sum is σ = 13100024. Its totient is φ = 13100022.

The previous prime is 13099991. The next prime is 13100027. The reversal of 13100023 is 32000131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13100023 - 25 = 13099991 is a prime.

It is a super-3 number, since 3×131000233 (a number of 22 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13099982 and 13100009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550011 + 6550012.

It is an arithmetic number, because the mean of its divisors is an integer number (6550012).

Almost surely, 213100023 is an apocalyptic number.

13100023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100023 is an equidigital number, since it uses as much as digits as its factorization.

13100023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 10.

The square root of 13100023 is about 3619.3953914984. The cubic root of 13100023 is about 235.7349737232.

Adding to 13100023 its reverse (32000131), we get a palindrome (45100154).

The spelling of 13100023 in words is "thirteen million, one hundred thousand, twenty-three".