Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …110001110111111000111 |
3 | 11122020100022110111121020 |
4 | 103010002032032333013 |
5 | 132430341042423421 |
6 | 2441450131522223 |
7 | 163434035630304 |
oct | 23040216167707 |
9 | 4566308414536 |
10 | 1310002311111 |
11 | 46562917560a |
12 | 191a79159373 |
13 | 966c0413820 |
14 | 47593b500ab |
15 | 241220dcdc6 |
hex | 1310238efc7 |
1310002311111 has 8 divisors (see below), whose sum is σ = 1881028959600. Its totient is φ = 806155268352.
The previous prime is 1310002311097. The next prime is 1310002311113. The reversal of 1310002311111 is 1111132000131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1310002311111 - 210 = 1310002310087 is a prime.
It is a super-2 number, since 2×13100023111112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310002311113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16794901386 + ... + 16794901463.
It is an arithmetic number, because the mean of its divisors is an integer number (235128619950).
Almost surely, 21310002311111 is an apocalyptic number.
1310002311111 is a deficient number, since it is larger than the sum of its proper divisors (571026648489).
1310002311111 is a wasteful number, since it uses less digits than its factorization.
1310002311111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33589802865.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 1310002311111 its reverse (1111132000131), we get a palindrome (2421134311242).
The spelling of 1310002311111 in words is "one trillion, three hundred ten billion, two million, three hundred eleven thousand, one hundred eleven".
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