131000254311231 has 12 divisors (see below), whose sum is σ = 195326544063040. Its totient is φ = 84516293103840.

The previous prime is 131000254311197. The next prime is 131000254311239. The reversal of 131000254311231 is 132113452000131.

131000254311231 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 0 + 0 + 2 + 543 + 112 + 3 + 1 = 666.

It is not a de Polignac number, because 131000254311231 - 2⁴² = 126602207800127 is a prime.

It is a super-2 number, since 2×131000254311231² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131000254311195 and 131000254311204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000254311239) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 234767480566 + ... + 234767481123.

Almost surely, 2^{131000254311231} is an apocalyptic number.

131000254311231 is a deficient number, since it is larger than the sum of its proper divisors (64326289751809).

131000254311231 is a wasteful number, since it uses less digits than its factorization.

131000254311231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 469534961726 (or 469534961723 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

The spelling of 131000254311231 in words is "one hundred thirty-one trillion, two hundred fifty-four million, three hundred eleven thousand, two hundred thirty-one".