Search a number
-
+
131000304013403 = 11371312457008159
BaseRepresentation
bin11101110010010011100010…
…100101100001000001011011
3122011211111200102111012020112
4131302103202211201001123
5114132302110311412103
61142340413040314535
736410313440424116
oct3562234245410133
9564744612435215
10131000304013403
1138816a0a498970
12128388a0912a4b
1358133778254c6
14244c63cb4157d
151022942862cd8
hex7724e296105b

131000304013403 has 16 divisors (see below), whose sum is σ = 147892235166720. Its totient is φ = 114987981794400.

The previous prime is 131000304013387. The next prime is 131000304013427. The reversal of 131000304013403 is 304310403000131.

It is not a de Polignac number, because 131000304013403 - 24 = 131000304013387 is a prime.

It is a super-2 number, since 2×1310003040134032 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131000304013433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1228450763 + ... + 1228557396.

It is an arithmetic number, because the mean of its divisors is an integer number (9243264697920).

Almost surely, 2131000304013403 is an apocalyptic number.

131000304013403 is a deficient number, since it is larger than the sum of its proper divisors (16891931153317).

131000304013403 is a wasteful number, since it uses less digits than its factorization.

131000304013403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2457008338.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 131000304013403 its reverse (304310403000131), we get a palindrome (435310707013534).

The spelling of 131000304013403 in words is "one hundred thirty-one trillion, three hundred four million, thirteen thousand, four hundred three".

Divisors: 1 11 37 131 407 1441 4847 53317 2457008159 27027089749 90909301883 321868068829 1000002320713 3540548757119 11909118546673 131000304013403