131000320121222 has 4 divisors (see below), whose sum is σ = 196500480181836. Its totient is φ = 65500160060610.

The previous prime is 131000320121171. The next prime is 131000320121233. The reversal of 131000320121222 is 222121023000131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131000320121222² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000320121194 and 131000320121203.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750080030304 + ... + 32750080030307.

It is an arithmetic number, because the mean of its divisors is an integer number (49125120045459).

Almost surely, 2^{131000320121222} is an apocalyptic number.

131000320121222 is a deficient number, since it is larger than the sum of its proper divisors (65500160060614).

131000320121222 is an equidigital number, since it uses as much as digits as its factorization.

131000320121222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65500160060613.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 131000320121222 its reverse (222121023000131), we get a palindrome (353121343121353).

The spelling of 131000320121222 in words is "one hundred thirty-one trillion, three hundred twenty million, one hundred twenty-one thousand, two hundred twenty-two".