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13100051 is a prime number
BaseRepresentation
bin110001111110…
…010000010011
3220122112220002
4301332100103
511323200201
61144440215
7216230366
oct61762023
926575802
1013100051
117438298
12447906b
132938913
141a500dd
15123b76b
hexc7e413

13100051 has 2 divisors, whose sum is σ = 13100052. Its totient is φ = 13100050.

The previous prime is 13100039. The next prime is 13100057. The reversal of 13100051 is 15000131.

13100051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13100051 - 222 = 8905747 is a prime.

It is a super-2 number, since 2×131000512 = 343222672405202, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13100057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550025 + 6550026.

It is an arithmetic number, because the mean of its divisors is an integer number (6550026).

Almost surely, 213100051 is an apocalyptic number.

13100051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100051 is an equidigital number, since it uses as much as digits as its factorization.

13100051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 13100051 is about 3619.3992595457. The cubic root of 13100051 is about 235.7351416764.

Adding to 13100051 its reverse (15000131), we get a palindrome (28100182).

The spelling of 13100051 in words is "thirteen million, one hundred thousand, fifty-one".