15000131 has 2 divisors, whose sum is σ = 15000132. Its totient is φ = 15000130.

The previous prime is 15000127. The next prime is 15000151. The reversal of 15000131 is 13100051.

It is a weak prime.

It is an emirp because it is prime and its reverse (13100051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15000131 - 2² = 15000127 is a prime.

It is a super-2 number, since 2×15000131² = 450007860034322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15000151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7500065 + 7500066.

It is an arithmetic number, because the mean of its divisors is an integer number (7500066).

Almost surely, 2^15000131 is an apocalyptic number.

15000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15000131 is an equidigital number, since it uses as much as digits as its factorization.

15000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 15000131 is about 3873.0002581978. Note that the first 3 decimals coincide. The cubic root of 15000131 is about 246.6219253727.

Adding to 15000131 its reverse (13100051), we get a palindrome (28100182).

The spelling of 15000131 in words is "fifteen million, one hundred thirty-one", and thus it is an aban number.