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13100102231261 is a prime number
BaseRepresentation
bin1011111010100001101011…
…1100001010010011011101
31201101100122122111202110012
42332220122330022103131
53204113002132400021
643510034234453005
72521310513464253
oct276503274122335
951340578452405
1013100102231261
1141a07a4210741
121576a79894165
13740446710116
143340968985d3
1517ab6c86735b
hexbea1af0a4dd

13100102231261 has 2 divisors, whose sum is σ = 13100102231262. Its totient is φ = 13100102231260.

The previous prime is 13100102231213. The next prime is 13100102231269. The reversal of 13100102231261 is 16213220100131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10592648983225 + 2507453248036 = 3254635^2 + 1583494^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100102231261 - 26 = 13100102231197 is a prime.

It is a super-2 number, since 2×131001022312612 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100102231269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550051115630 + 6550051115631.

It is an arithmetic number, because the mean of its divisors is an integer number (6550051115631).

Almost surely, 213100102231261 is an apocalyptic number.

It is an amenable number.

13100102231261 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100102231261 is an equidigital number, since it uses as much as digits as its factorization.

13100102231261 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13100102231261 its reverse (16213220100131), we get a palindrome (29313322331392).

The spelling of 13100102231261 in words is "thirteen trillion, one hundred billion, one hundred two million, two hundred thirty-one thousand, two hundred sixty-one".