13100111040000 has 400 divisors, whose sum is σ = 43733061440640. Its totient is φ = 3483540480000.

The previous prime is 13100111039989. The next prime is 13100111040011. The reversal of 13100111040000 is 4011100131.

It is an interprime number because it is at equal distance from previous prime (13100111039989) and next prime (13100111040011).

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×13100111040000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 344620995 + ... + 344659005.

Almost surely, 2^{13100111040000} is an apocalyptic number.

13100111040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100111040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21866530720320).

13100111040000 is an abundant number, since it is smaller than the sum of its proper divisors (30632950400640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100111040000 is an frugal number, since it uses more digits than its factorization.

13100111040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38411 (or 38380 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 13100111040000 its reverse (4011100131), we get a palindrome (13104122140131).

The spelling of 13100111040000 in words is "thirteen trillion, one hundred billion, one hundred eleven million, forty thousand".