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131001110414302 = 265500555207151
BaseRepresentation
bin11101110010010100010010…
…101001101100001111011110
3122011211120202121212121022111
4131302110102221230033132
5114132310233231224202
61142341025044304234
736410342431630132
oct3562242251541736
9564746677777274
10131001110414302
1138817293700897
1212838a869a207a
1358134759099bb
14244c6b7c953c2
15102298d5516d7
hex772512a6c3de

131001110414302 has 4 divisors (see below), whose sum is σ = 196501665621456. Its totient is φ = 65500555207150.

The previous prime is 131001110414287. The next prime is 131001110414333. The reversal of 131001110414302 is 203414011100131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1310011104143022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750277603574 + ... + 32750277603577.

It is an arithmetic number, because the mean of its divisors is an integer number (49125416405364).

Almost surely, 2131001110414302 is an apocalyptic number.

131001110414302 is a deficient number, since it is larger than the sum of its proper divisors (65500555207154).

131001110414302 is an equidigital number, since it uses as much as digits as its factorization.

131001110414302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65500555207153.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 131001110414302 its reverse (203414011100131), we get a palindrome (334415121514433).

The spelling of 131001110414302 in words is "one hundred thirty-one trillion, one billion, one hundred ten million, four hundred fourteen thousand, three hundred two".

Divisors: 1 2 65500555207151 131001110414302