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131001111241420 = 22572932266283557
BaseRepresentation
bin11101110010010100010010…
…101100110110001011001100
3122011211120202200102121220111
4131302110102230312023030
5114132310233434211140
61142341025114125404
736410342441643430
oct3562242254661314
9564746680377814
10131001111241420
1138817294116262
1212838a87120864
135813475b39314
14244c6b802c9c0
15102298d6667ea
hex772512b362cc

131001111241420 has 48 divisors (see below), whose sum is σ = 325244138264640. Its totient is φ = 43365885099264.

The previous prime is 131001111241417. The next prime is 131001111241421. The reversal of 131001111241420 is 24142111100131.

It is a super-2 number, since 2×1310011112414202 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001111241391 and 131001111241400.

It is not an unprimeable number, because it can be changed into a prime (131001111241421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16133137719 + ... + 16133145838.

It is an arithmetic number, because the mean of its divisors is an integer number (6775919547180).

Almost surely, 2131001111241420 is an apocalyptic number.

131001111241420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131001111241420 is an abundant number, since it is smaller than the sum of its proper divisors (194243027023220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001111241420 is a wasteful number, since it uses less digits than its factorization.

131001111241420 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32266283602 (or 32266283600 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 131001111241420 its reverse (24142111100131), we get a palindrome (155143222341551).

The spelling of 131001111241420 in words is "one hundred thirty-one trillion, one billion, one hundred eleven million, two hundred forty-one thousand, four hundred twenty".

Divisors: 1 2 4 5 7 10 14 20 28 29 35 58 70 116 140 145 203 290 406 580 812 1015 2030 4060 32266283557 64532567114 129065134228 161331417785 225863984899 322662835570 451727969798 645325671140 903455939596 935722223153 1129319924495 1871444446306 2258639848990 3742888892612 4517279697980 4678611115765 6550055562071 9357222231530 13100111124142 18714444463060 26200222248284 32750277810355 65500555620710 131001111241420