1310011131133 has 2 divisors, whose sum is σ = 1310011131134. Its totient is φ = 1310011131132.

The previous prime is 1310011131131. The next prime is 1310011131157. The reversal of 1310011131133 is 3311311100131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1105740577764 + 204270553369 = 1051542^2 + 451963^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310011131133 - 2¹ = 1310011131131 is a prime.

It is a super-2 number, since 2×1310011131133² (a number of 25 digits) contains 22 as substring.

Together with 1310011131131, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1310011131133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310011131131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655005565566 + 655005565567.

It is an arithmetic number, because the mean of its divisors is an integer number (655005565567).

Almost surely, 2^{1310011131133} is an apocalyptic number.

It is an amenable number.

1310011131133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310011131133 is an equidigital number, since it uses as much as digits as its factorization.

1310011131133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1310011131133 its reverse (3311311100131), we get a palindrome (4621322231264).

The spelling of 1310011131133 in words is "one trillion, three hundred ten billion, eleven million, one hundred thirty-one thousand, one hundred thirty-three".