Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1101000000100011101 |
3 | 110112010200201120100012 |
4 | 1322000101220010131 |
5 | 4121242241414401 |
6 | 140103040413005 |
7 | 12315221113412 |
oct | 1720021500435 |
9 | 415120646305 |
10 | 131001123101 |
11 | 5061479a7a2 |
12 | 21480017165 |
13 | c479415c74 |
14 | 64aa42a109 |
15 | 361abb78bb |
hex | 1e8046811d |
131001123101 has 2 divisors, whose sum is σ = 131001123102. Its totient is φ = 131001123100.
The previous prime is 131001123079. The next prime is 131001123131. The reversal of 131001123101 is 101321100131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72400817476 + 58600305625 = 269074^2 + 242075^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131001123101 is a prime.
It is a super-2 number, since 2×1310011231012 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001123131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500561550 + 65500561551.
It is an arithmetic number, because the mean of its divisors is an integer number (65500561551).
Almost surely, 2131001123101 is an apocalyptic number.
It is an amenable number.
131001123101 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001123101 is an equidigital number, since it uses as much as digits as its factorization.
131001123101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 131001123101 its reverse (101321100131), we get a palindrome (232322223232).
The spelling of 131001123101 in words is "one hundred thirty-one billion, one million, one hundred twenty-three thousand, one hundred one".
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