Base | Representation |
---|---|
bin | 10011000100000010110… |
… | …000100100100000000101 |
3 | 11122020100221101210200102 |
4 | 103010002300210200011 |
5 | 132430400343442013 |
6 | 2441451052453445 |
7 | 163434205266326 |
oct | 23040260444005 |
9 | 4566327353612 |
10 | 1310011312133 |
11 | 465633263177 |
12 | 191a8017a285 |
13 | 966c2245784 |
14 | 4759501444d |
15 | 24122cb9d58 |
hex | 13102c24805 |
1310011312133 has 16 divisors (see below), whose sum is σ = 1447722305280. Its totient is φ = 1179064862976.
The previous prime is 1310011312063. The next prime is 1310011312171. The reversal of 1310011312133 is 3312131100131.
It is a cyclic number.
It is not a de Polignac number, because 1310011312133 - 210 = 1310011311109 is a prime.
It is a super-2 number, since 2×13100113121332 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310011312633) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1257416 + ... + 2049662.
It is an arithmetic number, because the mean of its divisors is an integer number (90482644080).
Almost surely, 21310011312133 is an apocalyptic number.
It is an amenable number.
1310011312133 is a deficient number, since it is larger than the sum of its proper divisors (137710993147).
1310011312133 is a wasteful number, since it uses less digits than its factorization.
1310011312133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 796516.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1310011312133 its reverse (3312131100131), we get a palindrome (4622142412264).
The spelling of 1310011312133 in words is "one trillion, three hundred ten billion, eleven million, three hundred twelve thousand, one hundred thirty-three".
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