1310012001343 has 2 divisors, whose sum is σ = 1310012001344. Its totient is φ = 1310012001342.

The previous prime is 1310012001341. The next prime is 1310012001433. The reversal of 1310012001343 is 3431002100131.

Together with next prime (1310012001433) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310012001343 - 2¹ = 1310012001341 is a prime.

It is a super-2 number, since 2×1310012001343² (a number of 25 digits) contains 22 as substring.

Together with 1310012001341, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1310012001343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310012001341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006000671 + 655006000672.

It is an arithmetic number, because the mean of its divisors is an integer number (655006000672).

Almost surely, 2^{1310012001343} is an apocalyptic number.

1310012001343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310012001343 is an equidigital number, since it uses as much as digits as its factorization.

1310012001343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1310012001343 its reverse (3431002100131), we get a palindrome (4741014101474).

The spelling of 1310012001343 in words is "one trillion, three hundred ten billion, twelve million, one thousand, three hundred forty-three".