Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …0011110010111101010011 |
3 | 1201101100200221211211001011 |
4 | 2332220130003302331103 |
5 | 3204113021434310003 |
6 | 43510040145151351 |
7 | 2521311132215626 |
oct | 276503403627523 |
9 | 51340627754034 |
10 | 13100121010003 |
11 | 41a0803877465 |
12 | 1576a8402b557 |
13 | 74044a5866c1 |
14 | 334099185dbd |
15 | 17ab6e32646d |
hex | bea1c0f2f53 |
13100121010003 has 2 divisors, whose sum is σ = 13100121010004. Its totient is φ = 13100121010002.
The previous prime is 13100121010001. The next prime is 13100121010007. The reversal of 13100121010003 is 30001012100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100121010003 - 21 = 13100121010001 is a prime.
It is a super-2 number, since 2×131001210100032 (a number of 27 digits) contains 22 as substring.
Together with 13100121010001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13100121010001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550060505001 + 6550060505002.
It is an arithmetic number, because the mean of its divisors is an integer number (6550060505002).
Almost surely, 213100121010003 is an apocalyptic number.
13100121010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100121010003 is an equidigital number, since it uses as much as digits as its factorization.
13100121010003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13100121010003 its reverse (30001012100131), we get a palindrome (43101133110134).
The spelling of 13100121010003 in words is "thirteen trillion, one hundred billion, one hundred twenty-one million, ten thousand, three".
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