Base | Representation |
---|---|
bin | 11000011001101001… |
… | …11111110011111111 |
3 | 1020210222012010010101 |
4 | 30030310333303333 |
5 | 203312112340333 |
6 | 10003525021531 |
7 | 642430123411 |
oct | 141464776377 |
9 | 36728163111 |
10 | 13100121343 |
11 | 561274a071 |
12 | 26572548a7 |
13 | 130a0587ba |
14 | 8c3b8c9b1 |
15 | 51a12c67d |
hex | 30cd3fcff |
13100121343 has 2 divisors, whose sum is σ = 13100121344. Its totient is φ = 13100121342.
The previous prime is 13100121323. The next prime is 13100121361. The reversal of 13100121343 is 34312100131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13100121343 is a prime.
It is a super-2 number, since 2×131001213432 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13100121343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100121323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550060671 + 6550060672.
It is an arithmetic number, because the mean of its divisors is an integer number (6550060672).
Almost surely, 213100121343 is an apocalyptic number.
13100121343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100121343 is an equidigital number, since it uses as much as digits as its factorization.
13100121343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13100121343 its reverse (34312100131), we get a palindrome (47412221474).
The spelling of 13100121343 in words is "thirteen billion, one hundred million, one hundred twenty-one thousand, three hundred forty-three".
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