Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1111111111110010011 |
3 | 110112010200220112122111 |
4 | 1322000101333332103 |
5 | 4121242303033021 |
6 | 140103042450151 |
7 | 12315222002023 |
oct | 1720021777623 |
9 | 415120815574 |
10 | 131001221011 |
11 | 50614857311 |
12 | 21480063957 |
13 | c47944b6bb |
14 | 64aa453a83 |
15 | 361abd68e1 |
hex | 1e8047ff93 |
131001221011 has 2 divisors, whose sum is σ = 131001221012. Its totient is φ = 131001221010.
The previous prime is 131001220991. The next prime is 131001221023. The reversal of 131001221011 is 110122100131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131001221011 - 235 = 96641482643 is a prime.
It is a super-2 number, since 2×1310012210112 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131001220982 and 131001221000.
It is not a weakly prime, because it can be changed into another prime (131001221041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500610505 + 65500610506.
It is an arithmetic number, because the mean of its divisors is an integer number (65500610506).
Almost surely, 2131001221011 is an apocalyptic number.
131001221011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001221011 is an equidigital number, since it uses as much as digits as its factorization.
131001221011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 131001221011 its reverse (110122100131), we get a palindrome (241123321142).
The spelling of 131001221011 in words is "one hundred thirty-one billion, one million, two hundred twenty-one thousand, eleven".
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