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131001221120 = 2195711259
BaseRepresentation
bin111101000000001001…
…0000000000000000000
3110112010200220112210112
41322000102000000000
54121242303033440
6140103042450452
712315222002240
oct1720022000000
9415120815715
10131001221120
1150614857400
1221480063a28
13c47944b773
1464aa453b20
15361abd6965
hex1e80480000

131001221120 has 480 divisors, whose sum is σ = 401646168000. Its totient is φ = 40139489280.

The previous prime is 131001221119. The next prime is 131001221167. The reversal of 131001221120 is 21122100131.

It is a super-2 number, since 2×1310012211202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 131001221095 and 131001221104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2220359651 + ... + 2220359709.

It is an arithmetic number, because the mean of its divisors is an integer number (836762850).

Almost surely, 2131001221120 is an apocalyptic number.

131001221120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131001221120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200823084000).

131001221120 is an abundant number, since it is smaller than the sum of its proper divisors (270644946880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001221120 is an frugal number, since it uses more digits than its factorization.

131001221120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131 (or 84 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 131001221120 its reverse (21122100131), we get a palindrome (152123321251).

The spelling of 131001221120 in words is "one hundred thirty-one billion, one million, two hundred twenty-one thousand, one hundred twenty".