1310012325533 has 2 divisors, whose sum is σ = 1310012325534. Its totient is φ = 1310012325532.

The previous prime is 1310012325529. The next prime is 1310012325539. The reversal of 1310012325533 is 3355232100131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1306419282169 + 3593043364 = 1142987^2 + 59942^2 .

It is an emirp because it is prime and its reverse (3355232100131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310012325533 - 2² = 1310012325529 is a prime.

It is a super-2 number, since 2×1310012325533² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310012325496 and 1310012325505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310012325539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006162766 + 655006162767.

It is an arithmetic number, because the mean of its divisors is an integer number (655006162767).

Almost surely, 2^{1310012325533} is an apocalyptic number.

It is an amenable number.

1310012325533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310012325533 is an equidigital number, since it uses as much as digits as its factorization.

1310012325533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 1310012325533 its reverse (3355232100131), we get a palindrome (4665244425664).

The spelling of 1310012325533 in words is "one trillion, three hundred ten billion, twelve million, three hundred twenty-five thousand, five hundred thirty-three".