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131001234334 = 265500617167
BaseRepresentation
bin111101000000001001…
…0000011001110011110
3110112010200221012220221
41322000102003032132
54121242303444314
6140103043031554
712315222055615
oct1720022031636
9415120835827
10131001234334
1150614866323
122148006b5ba
13c479454799
1464aa45887c
15361abda824
hex1e8048339e

131001234334 has 4 divisors (see below), whose sum is σ = 196501851504. Its totient is φ = 65500617166.

The previous prime is 131001234313. The next prime is 131001234341. The reversal of 131001234334 is 433432100131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 433432100131 = 1451298712681.

It is a super-2 number, since 2×1310012343342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001234299 and 131001234308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750308582 + ... + 32750308585.

It is an arithmetic number, because the mean of its divisors is an integer number (49125462876).

Almost surely, 2131001234334 is an apocalyptic number.

131001234334 is a deficient number, since it is larger than the sum of its proper divisors (65500617170).

131001234334 is an equidigital number, since it uses as much as digits as its factorization.

131001234334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65500617169.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 131001234334 its reverse (433432100131), we get a palindrome (564433334465).

The spelling of 131001234334 in words is "one hundred thirty-one billion, one million, two hundred thirty-four thousand, three hundred thirty-four".

Divisors: 1 2 65500617167 131001234334