Base | Representation |
---|---|
bin | 111101000000001001… |
… | …0000111100100101101 |
3 | 110112010200222010100110 |
4 | 1322000102013210231 |
5 | 4121242310032031 |
6 | 140103043250233 |
7 | 12315222161544 |
oct | 1720022074455 |
9 | 415120863313 |
10 | 131001252141 |
11 | 50614878741 |
12 | 21480079979 |
13 | c47945c916 |
14 | 64aa46115b |
15 | 361abe0c46 |
hex | 1e8048792d |
131001252141 has 4 divisors (see below), whose sum is σ = 174668336192. Its totient is φ = 87334168092.
The previous prime is 131001252127. The next prime is 131001252143. The reversal of 131001252141 is 141252100131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 131001252141 - 26 = 131001252077 is a prime.
It is a super-2 number, since 2×1310012521412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131001252143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21833542021 + ... + 21833542026.
It is an arithmetic number, because the mean of its divisors is an integer number (43667084048).
Almost surely, 2131001252141 is an apocalyptic number.
It is an amenable number.
131001252141 is a deficient number, since it is larger than the sum of its proper divisors (43667084051).
131001252141 is an equidigital number, since it uses as much as digits as its factorization.
131001252141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43667084050.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 131001252141 its reverse (141252100131), we get a palindrome (272253352272).
The spelling of 131001252141 in words is "one hundred thirty-one billion, one million, two hundred fifty-two thousand, one hundred forty-one".
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