Base | Representation |
---|---|
bin | 111101000000001001… |
… | …0000111100100101111 |
3 | 110112010200222010100112 |
4 | 1322000102013210233 |
5 | 4121242310032033 |
6 | 140103043250235 |
7 | 12315222161546 |
oct | 1720022074457 |
9 | 415120863315 |
10 | 131001252143 |
11 | 50614878743 |
12 | 2148007997b |
13 | c47945c918 |
14 | 64aa46115d |
15 | 361abe0c48 |
hex | 1e8048792f |
131001252143 has 2 divisors, whose sum is σ = 131001252144. Its totient is φ = 131001252142.
The previous prime is 131001252127. The next prime is 131001252169. The reversal of 131001252143 is 341252100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131001252143 - 24 = 131001252127 is a prime.
It is a super-2 number, since 2×1310012521432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001252113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500626071 + 65500626072.
It is an arithmetic number, because the mean of its divisors is an integer number (65500626072).
Almost surely, 2131001252143 is an apocalyptic number.
131001252143 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001252143 is an equidigital number, since it uses as much as digits as its factorization.
131001252143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 131001252143 its reverse (341252100131), we get a palindrome (472253352274).
The spelling of 131001252143 in words is "one hundred thirty-one billion, one million, two hundred fifty-two thousand, one hundred forty-three".
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