Base | Representation |
---|---|
bin | 1011111010100001110100… |
… | …1110010001000110010111 |
3 | 1201101100202022120122100111 |
4 | 2332220131032101012113 |
5 | 3204113041434011434 |
6 | 43510042123423451 |
7 | 2521311460154464 |
oct | 276503516210627 |
9 | 51340668518314 |
10 | 13100140532119 |
11 | 41a08138a0743 |
12 | 1576a8a684b87 |
13 | 740451630454 |
14 | 33409b9c866b |
15 | 17ab70dd0964 |
hex | bea1d391197 |
13100140532119 has 2 divisors, whose sum is σ = 13100140532120. Its totient is φ = 13100140532118.
The previous prime is 13100140532111. The next prime is 13100140532153. The reversal of 13100140532119 is 91123504100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100140532119 - 23 = 13100140532111 is a prime.
It is a super-2 number, since 2×131001405321192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100140532111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550070266059 + 6550070266060.
It is an arithmetic number, because the mean of its divisors is an integer number (6550070266060).
Almost surely, 213100140532119 is an apocalyptic number.
13100140532119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100140532119 is an equidigital number, since it uses as much as digits as its factorization.
13100140532119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 31.
The spelling of 13100140532119 in words is "thirteen trillion, one hundred billion, one hundred forty million, five hundred thirty-two thousand, one hundred nineteen".
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